Respuesta :

Answer:

2(3x^3+2y^2)= 0

Step-by-step explanation:

2(3x^3+2y^2)

[tex]2(3*-2^{3} +2*\sqrt{12^{2} }) \\2(3*-8+2*12^{2}^\frac{1}{2} } )\\2(3*-8+2*12)\\2(-24+24)\\2*0\\0[/tex]