The probability of selecting 50 jars is 0%
The z score determines by how many standard deviations the raw score is above or below the mean. It is given by:
[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} } \\\\where \mu=mean,\sigma=standard\ deviation, x=raw\ score,n=sample\ size\\\\Given\ that\ \mu=17,\sigma=0.68,n=50,x=16.8\\\\z=\frac{16.8-17}{0.65/\sqrt{50} } =-5[/tex]
The P(z < -5) = 0%
Therefore the probability of selecting 50 jars is 0%
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