mads1219
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It’s linear so you map out the first differences and then put it into y=Mx+b form. For the you gotta find the y intercept

Its linear so you map out the first differences and then put it into yMxb form For the you gotta find the y intercept class=

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DᴀʀᴋPᴀʀᴀᴅᴏx

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Let's find the slope (m) :

  • [tex] \dfrac{y2 - y1}{x2 - x1} [/tex]

  • [tex] \dfrac{16 - 11}{9 - 6} [/tex]

  • [tex] \dfrac{5}{3} [/tex]

slope of given line is 5/3

now, let's plug the value of coordinates of a point lying on the line ( for example : (6 , 11) and slope (m) to find the y - intercept (c) :

  • [tex]y = mx + c[/tex]

  • [tex]11 = \bigg(\dfrac{5}{ 3} \times 6 \bigg) + c[/tex]

  • [tex]11 = (5 \times 2) + c[/tex]

  • [tex]11 = 10 + c[/tex]

  • [tex]c = 11 - 10[/tex]

  • [tex]c = 1[/tex]

value of y - intercept (c) = 1, so our equation will be :

  • [tex]y = mx + c[/tex]

  • [tex]y = \dfrac{5}{3}x + 1[/tex]

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