Answer:
[tex]f(4) = 2[/tex]
Step-by-step explanation:
1. [tex]f(n)=5n+8[/tex]
[tex]f(4)=\\\\f(-2)[/tex]
Replace [tex]n[/tex] with [tex]4[/tex]; solve
[tex]f(n)=5n+8\\\\f(n)=5(4)+8\\\\5(4)\\\\20+8\\\\28[/tex]
Therefore, [tex]f(4) = 28[/tex]
Replace [tex]n[/tex] with [tex]-2[/tex]
[tex]f(n)=5n+8\\\\f(n)=5(-2)+8\\\\5(-2)\\\\-10+8\\\\-2[/tex]
Therefore, [tex]f(-2) = -2[/tex]
2. [tex]f(n)=-2n+1[/tex]
[tex]f(10)=\\\\f(-1)=[/tex]
Replace n with 10; solve
[tex]f(n)=-2n+1\\\\f(n)=-2(10)+1\\\\-2(10)\\\\-20+1\\\\-19[/tex]
