Values for the area A of the rectangle shown are 12 ≤ A ≤ 36.

A rectangle of length 2x and width 3.

A compound inequality for this situation is 12 ≤
Choose...
≤ 36.
Part B

The solution of the compound inequality in Part A is

Respuesta :

A compound inequality is used to combined multiple inequalities.

  • The compound inequality is: [tex]12 \le 6x \le 36[/tex].
  • The solution to the compound inequality is: [tex]2 \le x \le 6[/tex]

We have:

[tex]12 \le A \le 36[/tex]

[tex]Length = 2x[/tex]

[tex]Width = 3[/tex]

The area of the rectangle is:

[tex]A = Length \times Width[/tex]

So, we have:

[tex]A =2x \times 3[/tex]

[tex]A = 6x[/tex]

Substitute 6x for A in [tex]12 \le A \le 36[/tex]

[tex]12 \le 6x \le 36[/tex]

Divide through by 6

[tex]2 \le x \le 6[/tex]

Hence,

  • The compound inequality is: [tex]12 \le 6x \le 36[/tex].
  • The solution to the compound inequality is: [tex]2 \le x \le 6[/tex]

Read more about compound inequalities at:

https://brainly.com/question/17957246