bhartman95
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Coasting due west on your bicycle at 8 m/s, you encounter a sandy patch of road 7.2m
across. When you leave the sandy patch your speed has been reduced to 6.5 m/s. Assuming
the bicycle slows with constant acceleration, what was its acceleration in the sandy patch?
Give your answer in m/s2 and round to the nearest tenth. (0.0)

Respuesta :

Answer:

V = (v1 + v2) / 2 = (8 + 6.5) / 2 = 7.25 m/s     average speed

t = 7.2 / 7.25 = .993 sec      time to cross patch

a = (v2 - v1) / t = (6.5 - 8) / .993 = -1.51 m/s^2     or 1.5 m/s^2

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