Using the concept of probability and the combination formula, it is found that there is a 0.4444 = 44.44% probability they get to be on the same team.
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Combination formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
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Finding the number of desired outcomes:
[tex]D = 2C_{8,3} = 2\frac{8!}{3!5!} = 112[/tex]
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Finding the number of total outcomes:
[tex]T = C_{10,5} = \frac{10!}{5!5!} = 252[/tex]
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The probability is:
[tex]p = \frac{D}{T} = \frac{112}{252} = 0.4444[/tex]
0.4444 = 44.44% probability they get to be on the same team.
A similar problem is given at https://brainly.com/question/22931444