We have that The speed of the water as it exits the hole is most nearly
V=14.8m/s
From the question we are told that
Generally the equation for the Torricelli's Law is mathematically given as
[tex]V=\sqrt{2gh}[/tex]
Where
[tex]H=12-1H=11\\\\Therefore\\\\\V=\sqrt{2*9.8*11}\\\\V=14.8m/s[/tex]
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