Using the concept of probability and the arrangements formula, there is a
0.002 = 0.2% probability that the first 8 people in line are teachers.
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The number of possible arrangements from a set of n elements is given by:
[tex]A_n = n![/tex]
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The desired outcomes are:
Thus, [tex]D = 8! \times 4![/tex]
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For the total outcomes, number of arrangements of 12 people, thus:
[tex]T = 12![/tex]
The probability is:
[tex]p = \frac{D}{T} = \frac{8! \times 4!}{12!} = 0.002[/tex]
0.002 = 0.2% probability that the first 8 people in line are teachers.
A similar problem is given at https://brainly.com/question/24650047