Charge q1 is distance r from a positive point charge Q. Charge q2=q1/3 is distance 2r from Q. What is the ratio U1/U2 of their potential energies due to their interactions with Q?

Charge q1 is distance s from the negative plate of a parallel-plate capacitor. Charge q2=q1/3 is distance 2s from the negative plate. What is the ratio U1/U2 of their potential energies?

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okpalawalter8 okpalawalter8 · Answer 1 · 2021-09-20T17:30:14+02:00

We have that The ratio U1/U2 of their potential energies due to their interactions with Q is

From the question we are told that

Question 1

Charge q1 is distance r from a positive point charge Q.

Question 2

Charge q2=q1/3 is distance 2r from Q.

Charge q1 is distance s from the negative plate of a parallel-plate capacitor.

Charge q2=q1/3 is distance 2s from the negative plate.

Generally the equation for the potential energy is mathematically given as

[tex]U=\frac{-k*qQ}{r}[/tex]

Therefore

The Equations of U1 and U2 is

For U1

[tex]U1=\frac{-k*q_1Q}{r}[/tex]

For U2

[tex]U2=\frac{-k*q_1Q}{3*2r}[/tex]

Since

U is a function of q and q2=q1/3

Therefore

[tex]U1/U2=6[/tex]

For Question 2

For U1

[tex]U1=\frac{-k*q_1Q}{s}\\\\For U2\\\\U2=\frac{-k*q_1Q}{3*2r}[/tex]

Therefore

[tex]U1/U2=6[/tex]

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