Answer:
(- [tex]\frac{1}{3}[/tex], [tex]\frac{3}{4}[/tex] )
Step-by-step explanation:
9x + 8y = 3 → (1)
6x - 12y = - 11 → (2)
Multiplying (1) by 12 and (2) by 8 and adding will eliminate the y- term
108x + 96y = 36 → (3)
48x - 96y = - 88 → (4)
Add (3) and (4) term by term to eliminate y
156x = - 52 ( divide both sides by 156 )
x = [tex]\frac{-52}{156}[/tex] = - [tex]\frac{1}{3}[/tex]
Substitute this value into either of the 2 equations and solve for y
Substituting into (1)
9(- [tex]\frac{1}{3}[/tex] ) + 8y = 3
- 3 + 8y = 3 ( add 3 to both sides )
8y = 6 ( divide both sides by 8 )
y = [tex]\frac{6}{8}[/tex] = [tex]\frac{3}{4}[/tex]
solution is (- [tex]\frac{1}{3}[/tex], [tex]\frac{3}{4}[/tex] )
