How do you determine whether (6,2) is on the line y=1/2x+2

If I go on desmos, or just by hand and graph y=1/2x+2, I can see the points it goes through. Once I graph my equation, I will specifically type another coordinate "(6,2)" to see if it is directly in my line. For your equation, (6,2) is not in the line of y=1/2x+2.

I really hope this helps, ask anything else if needed.

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Happil Happil · Answer 2 · 2021-09-14T05:28:53+02:00

Answer:

If the point [tex](6,2)[/tex] does satisfy the equation, [tex]y = \frac{1}{2}x +2\\[/tex], the point is on the line. Otherwise it's not.

Step-by-step explanation:

Points that are on the line actually satisfy the equations of their respective lines. If the point [tex](6,2)[/tex] does satisfy the equation, [tex]y = \frac{1}{2}x +2\\[/tex], the point is on the line. Otherwise it's not.

Testing if [tex](6,2)[/tex] is on the line, [tex]y = \frac{1}{2}x +2\\[/tex]:

[tex]y = \frac{1}{2}x +2 \\ 2 \stackrel{?}{=} \frac{1}{2}(6) +2 \\ 2 \stackrel{?}{=} 3 +2 \\ 2 \stackrel{?}{=} 3 +2 \\ 2 \stackrel{?}{=} 5 \\ 2 \neq 5[/tex]

The point [tex](6,2)[/tex] does not satisfy the equation, [tex]y = \frac{1}{2}x +2\\[/tex], so the point is not on the line.