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You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length.
Suppose that the perimeter of a rectangle is 62 feet, and the length is 13 feet more than the width. Find the width of the
rectangle, in feet.

You may remember that the perimeter of a rectangle is P2WL where W is the width and L is the length Suppose that the perimeter of a rectangle is 62 feet and the class=

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Step-by-step explanation:

So, x=width and the width=13+L. The formula for perimeter is 2(L)+2(W) and the total perimeter in this question is 62 feet. That means 2(L)+2(13+L)=62 feet. Solve for L and that's going to be your length. Add the length plus 13 and you'll have the width. Double check the equation by plugging the width and length back into the equation. (Does that help?)

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