help lol i dont get it

[tex]9) s^{2}=81 \\s=\sqrt{81} ,s=-\sqrt{81} \\\sqrt{81}=9\\-\sqrt{81} =-9\\s=9,s=-9[/tex]
[tex]12) r=\frac{12}{13}, r=-\frac{12}{13} \\\\11) d=\frac{1}{10} ,d=-\frac{1}{10}[/tex]
Step-by-step explanation:
Its all about the square root I believe
Answer:
9. 9
10. 6
11. 0.01
12. 0.923 (round to whatever you are supposed to)
1. 2 and 2.2
2. 4 and 4.2
3. 6 and 6.4
Step-by-step explanation:
9. isolate s by finding the square root of both sides (sqrt of 81=9)
10. do the same thing as 9 (sqrt 36=6)
11. same as 9 + 10 (sqrt of 1/100 = 0.01)
12. same as 9+10+11 (sqrt of 144/169=0.923)
1. find the square root of 5 then round
2. find the square root of 18 then round
3. find the square root of 41 then round
I hope this helps!