The distance of the house located 8 miles north on the eastern boundary of the tower is 11.31 miles east of the town.
(a) the diagram of this situation is in the image added.
(b) the distance of the house located 8 miles north on the eastern boundary of the tower is calculated by applying Pythagoras theorem.
[tex]c^2 = a^2 + b^2\\\\c^2 = (8)^2 + (4+ 4)^2 \\\\c^2 = (64) + (64)\\\\c^2 = 128\\\\c = \sqrt{128} \\\\c = 11.31 \ miles \ east \ of \ the \ town[/tex]
Thus, the distance of the house located 8 miles north on the eastern boundary of the tower is 11.31 miles east of the town.
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