Answer:
b(t) = (t -5) (t+3) (t-2)
zero of the function is given by
b(t) = (t -5) (t+3) (t-2)=0
such that
(t -5) (t+3) (t-2)=0
i.e., (t -5)=0 and (t+3) =0 and (t-2)=0
consider (t -5)=0
t -5 =0
t+5-5=0+5
t=5
consider (t +3)=0
t +3 =0
t+3-3=0-3
t= -3
consider (t -2)=0
t -2 =0
t+2-2=0+2
t=2
answer is B
Step-by-step explanation:
