Answer:
0.60g of the fungus can be allowed
Explanation:
The maximum concentration of the fungus that can be allowed is 25 ppb, that is 25mg/t.
As the peanuts are 24t, the mass of fungus that can be allowed is:
24t * (25mg/t) = 600mg of the fungus can be allowed. In grams are:
600mg * (1g/1000mg) =
Answer:
0.5g of toxin
Explanation:
ppb = mass of solute/ mass of solution x 10^9
ppb = mass of fungus/ mass of peanuts x 10^9
25ppb = (x/2 x 10^7g) x 10^9
x = (25)(2 x 10^7g)/ 10^9
x = 0.5g of toxin
x represented the unknown mass of solute (fungus), in which we solved for. We already knew we were using the ppb formula, which is mass of solute/ mass of solution x 10^9, because the question mentions that there are 25ppb of peanuts in the shipments. In the calculations, you can see that I substituted the mass of peanuts with 2 x 10^7g. I did this because the question mentions that there are 20t of peanuts and since each t = 1000kg, I multiped 20 x 1000 to get 20 000kg. In my formula for ppb, I know that I have to use grams of solution, not kilograms. Knowing this, we follow the formula for ppb and substitute our known values and solving for unknown values.
