Answer:
N = 42
Explanation:
Given that,
Angular velocity, [tex]\omega=1800\ rad/s[/tex]
Peak emf, [tex]\epsilon=18\ V[/tex]
The dimensions of the rectangular coil = 1.00 cm by 3.00 cm
Magnetic field, B = 0.794 T
We know that, the emf of the coil is given by :
[tex]\epsilon=NAB\omega[/tex]
Where
N is number of turns in the coil
So,
[tex]N=\dfrac{\epsilon}{AB\omega}\\\\N=\dfrac{18}{0.01\times 0.03\times 0.794\times 1800}\\\\N=41.98[/tex]
or
N = 42
So, there are 42 turns in the coil.
