Answer:
The height of water increasing is 8.5 x 10^-4 m/s.
Explanation:
radius, r = 5 m
Volume per second, dV/dt = 2 m^3/min = 2/60 m^3/s
Let the height of cylinder is h.
The volume of the cylinder is given by
[tex]V = \pi r^2 h \\\\\frac{dV}{dt} = \pi r^2 \frac{dh}{dt}\\\\\frac{2}{30} = 3.14\times 5\times 5\times \frac{dh}{dt}\\\\\frac{dh}{dt}=8.5 \times 10^{-4} m/s[/tex]
