9514 1404 393
Answer:
528
Step-by-step explanation:
The sum can be decomposed into parts that may be easier to figure.
[tex]\displaystyle\sum_{n=1}^{24}(2n-3)=2\sum_{n=1}^{24}(n)-3\sum_{n=1}^{24}(1)=2\dfrac{24\cdot25}{2}-3\cdot24\\\\=600-72=\boxed{528}[/tex]
