Answer:
[tex]y=-2x+6[/tex]
Step-by-step explanation:
Slope-intercept form is given as [tex]y=mx+b[/tex], where [tex]m[/tex] is slope and [tex]b[/tex] is the y-intercept.
To find the slope of a line that passes through two points [tex](x_1, x_2)[/tex] and [tex](y_1, y_2)[/tex], use the slope formula:
[tex]m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}[/tex]
Let:
[tex](x_1, y_1)\implies (1, 4)\\(x_2, y_2)\implies (0, 6)[/tex]
The slope of the line that passes through these two points is:
[tex]m=\frac{6-4}{0-1}=\frac{2}{-1}=-2[/tex]
Now substitute [tex]m=-2[/tex] and any point to solve for [tex]b[/tex]:
[tex]y=mx+b,\\6=-2(0)+b,\\6=0+b,\\b=6[/tex]
Therefore, the slope-intercept form of a line that is represented by the table is [tex]\boxed{y=-2x+6}[/tex]
