Respuesta :

VirαtKσhli

Answer:

x = 3.3

Step-by-step explanation:

A equation is given to us and we need to solve out for x. The given equation is ,

[tex]\sf\longrightarrow 5^{x -2}= 8 [/tex]

Take log on both sides with base as " 10" . We have ,

[tex]\sf\longrightarrow log_{10} 5^{x-2}= log_{10}\ 8[/tex]

Simplify using the property of log , [tex]\sf log a^m = m log a [/tex] , we have ,

[tex]\sf\longrightarrow ( x -2) log_{10} 5 = log_{10} 8 [/tex]

Simplify ,

[tex]\sf\longrightarrow ( x -2 ) log_{10}5 = log_{10} 2^3[/tex]

Again simplify using the property of log ,

[tex]\sf\longrightarrow (x-2) log 5 = 3 log 2[/tex]

We know that log 5 = 0.69 and log 2 = 0.301 , on substituting this , we have ,

[tex]\sf\longrightarrow ( x - 2 ) = \dfrac{ 3\times 0.301}{0.69}[/tex]

Simplify the RHS ,

[tex]\sf\longrightarrow x - 2 = 1.30 [/tex]

Add 2 both sides ,

[tex]\sf\longrightarrow \boxed{\blue{\sf x = 3.30}}[/tex]

Hence the Value of x is 3.30 .

Answer:

its actually 3.292 because we round to the nearest thousandth and thats not even the equation you use above

Step-by-step explanation:

For this equation we use the formula log a^m=m (log a) so the equation will be written as log 5 (5^x-2) = log 5 (8). You use the base, which is 5, and use log to base 5 on both sides of the equation. Then you take the exponent " x-2" and write( x-2) log 5 (5) = log 5(8). Since log a =1, you multiply that 1 by x-2, which keeps it x-2. Making the equation x-2 = log 5 (8). Next, we use the change of the base properties with the formula log b^y= log y/ log b. The equation will be written as x-2 = log 8/ log 5, since 5 is the base it stays in the bottom or basement. We then add +2 to both sides of x-2 and log 8/ log 5. To solve this equation, you can find out what log 8 and log 5 are and divide those and add +2 to solve. So log 8 = 0.903 and log 5 = 0.698970 and divide those to get 1.29190 +2 and you get the answer rounded as 3.292. 

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