Answer:
Please find the complete question in the attachment.
Step-by-step explanation:
The likelihood of the part of claims that is less than 0.05 for all the houses is calculated as:
[tex]P(X < 0.05) = int^{0.05}_{0} int^{1-x}_{0} f(x,y) \ dy\ dx\\\\[/tex]
[tex]= \int^{0.05}_{0} \int^{1-x}_{0} 6(1-x-y) \ dy\ dx\\\\= \int^{0.05}_{0} 6((1-x)-x(1-x)-\frac{(1-x)^2}{2}) \ dx\\\\ = \int^{0.05}_{0} 6(1-2x+x^2-0.5-0.5x^2+x) \ dx\\\\= \int^{0.05}_{0} 6(0.5x^2-x+0.5) \ dx\\\\= 6(0.5\times \frac{0.05^3}{3} -\frac{0.05^2}{2}+0.5 \times 0.05 )\\\\ =0.1426\\\\[/tex]
