Respuesta :
Answer:
[tex]sec~y=\frac{q}{r}[/tex]
Step-by-step explanation:
[tex]tan ~y=\frac{7}{r} \\\\\frac{sin~y}{cos~y} =\frac{7}{r} \\\\sin~y=\frac{7}{r} cos~y\\sin ~y=\frac{7}{q} \\\frac{7}{q} =\frac{7}{r} cos~y\\sec~y=\frac{7}{r} \times \frac{q}{7} =\frac{q}{r}[/tex]
The tangent is equal to the product of the sine and secant. The value of sec y is q over r, then the correct option is A.
What is a right-angle triangle?
It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function. The Pythagoras is the sum of the square of two sides is equal to the square of the longest side.
If sin y = 7/q and tan y = 7/r.
Then the value of sec y will be
We know that the identity
[tex]\sec x =\dfrac{\tan x}{\sin x}[/tex]
Then we have
[tex]\rm \sec y = \dfrac{7/r}{7/q} \\\\\\\sec y = \dfrac{q}{r}[/tex]
The value of sec y is q over r.
More about the right-angle triangle link is given below.
https://brainly.com/question/3770177
