Answer:
[tex]\boxed {\boxed {\sf 1 \ real \ root}}[/tex]
Step-by-step explanation:
The quadratic formula is used to find the roots or zeroes of a quadratic equation. It is:
[tex]x=\frac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}[/tex]
The discriminant helps us find the number of roots. If the discriminant is...
It is the expression under the square root symbol:
[tex]b^2-4ac[/tex]
First, we must put the given quadratic equation into standard form, which is:
[tex]ax^2+bx+c=0[/tex]
The equation given is [tex]x^2 +14x= -49[/tex]. We have to move the -49 to the left side. Since it is a negative number, we add 49 to both sides.
[tex]x^2+14x+49 = -49 +49 \\x^2+14x+49=0[/tex]
Now we can solve for the discriminant because we know that:
Substitute these values into the formula for the discriminant.
[tex](14)^2 -4 (1)(49)[/tex]
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.
Solve the exponent.
[tex]196- 4(1)(49)[/tex]
Multiply 4, 1, and 49.
[tex]196-196[/tex]
Subtract.
[tex]0[/tex]
The discriminant is zero, so the quadratic equation x²+ 14x = -49 has 1 real root.
