Answer:
4628
Step-by-step explanation:
We are given that
In 2000
The population of a small industrial town in 2000=12910
Depreciation rate, r=5% per year
We have to find the population in the year 2020.
Time from 2000 to 2020=20 years
[tex]FV=PV(1-\frac{r}{100})^n[/tex]
Where FV=Future value
PV=Present value
Using the formula
[tex]FV=12910(1-\frac{5}{100})^{20}[/tex]
[tex]FV=12910(\frac{95}{100})^{20}[/tex]
FV=4628
Hence, the population in 2020 =4628
