Answer:
-0.383 m
Explanation:
Diameter of cylinder = 4m therefore r = 2
height of cylinder ( H ) = 4 m
specific gravity = 0.6 ( assumed )
depth of immersion = 'h'
Determine the metacentric height
weight of cylinder in water = water displaced
= 0.6 * 1000 * πr^2* H = 1000 * πr^2* h
= 0.6 * 4 = h
∴ h = 2.4 m
hence the depth of center of buoyancy from free space = h /2 = 1.2 m
The metacentric height can be calculated using the formula below
Gm = Io / Vsubmerged - BG
attached below is the remaining solution
