Q3. (a) The student places 0.5 kg of potato into a pan of water.
During cooking, the temperature of the potato increases from 20 °C to 100°C
The specific heat capacity of the potato is 3400 J/kg °C
80
Calculate the change in thermal energy of the potato. Use the equation:
change in thermal energy = mass * specific heat capacity * temperature change
m = 0.5kg
C = 34001
TA= 20° - 100°
° = 80°C
OʻS x 3400 x 80 - 136000J
136000
Change in thermal energy =
(b) Why is the energy supplied by the cooker greater than that calculated in part (a)?
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Answer:

136000 J or 136 kJ

Explanation:
Formula
Heat = m * c * deltaH
Givens
m= 0.5 kg
c = 3400 J / (kg * oC)
Deltat = (100oC - 20oC)
deltat = 80oC
Solution
Heat = 0.5 kg * 3400 J/(kg* oC) * 80oC
Heat = 136000 Joules
Heat = 136 kg
Technically there is only 1 place of accuracy.