lizews2006
contestada

Hi, I need this answer urgently.

Factorise completely
[tex]12 {x}^{2} {y}^{2} - 1 - 3 {x}^{2} + 4 {y}^{2} [/tex]
Please explain too. Thanks! ​

Respuesta :

Answer:

[tex]12x {}^{2} y { }^{2} - 1 - 3x {}^{2} + 4y {}^{2} \\ = (12x {}^{2}y {}^{2} - 3x {}^{2} ) + (4y {}^{2} - 1) \\ = 3x {}^{2} (4y {}^{2} - 1) + (4y {}^{2} - 1) \\ = (3x {}^{2} + 1)(4y {}^{2} - 1) \\ = (3x {}^{2} + 1)(2y - 1)(2y + 1)[/tex]

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