Answer:
The appropriate solution is Option D (22 m/sec).
Step-by-step explanation:
The given equation is:
[tex]s(t)= -(t-15)^2 + 225[/tex]
Now,
The instantaneous velocity at t = 4 will be:
= [tex][-2(t-15)(1)+0][/tex]
= [tex]-2(4-15)[/tex]
= [tex]-2\times (-11)[/tex]
= [tex]22 \ m/sec[/tex]
Thus, the above is the correct option.