Respuesta :

Cricetus

The solute potential will be "-24.4658 liter-atm".

Given values are:

Concentration,

  • C = 1.0 M

Temperature (in Kelvin),

  • T = 25+273

           = 298

Ionization constant,

  • i = 1

Universal gas constant,

  • R = 0.0821 \ liter-atm/mol-K

The solute potential will be:

→ [tex]\psi_s = -iCRT[/tex]

By substituting the given values, we get

→      [tex]= -(1\times 1\times 0.0821\times 298)[/tex]

→      [tex]= - 24.4658 \ liter-atm[/tex]

Thus the above solution is correct.

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