Answer:
[tex]\huge \purple {\boxed { m\angle C = 47\degree}} [/tex]
[tex] \huge \red {\boxed { \widehat{BC}=96\degree}} [/tex]
Step-by-step explanation:
By inscribed angle theorem:
[tex] m\angle C = \frac{1}{2} m(\widehat{AD}) [/tex]
[tex] \therefore m\angle C = \frac{1}{2}\times 94\degree [/tex]
[tex]\huge \purple {\boxed {\therefore m\angle C = 47\degree}} [/tex]
Again by inscribed angle theorem:
[tex] m\angle A = \frac{1}{2} m(\widehat{BC}) [/tex]
[tex] \therefore 48\degree = \frac{1}{2} m(\widehat{BC}) [/tex]
[tex] \therefore 48\degree\times 2 = m(\widehat{BC}) [/tex]
[tex] \huge \red {\boxed {\therefore m(\widehat{BC}) =96\degree}} [/tex]
