Answer: [tex]11.78\ in.^3[/tex]
Step-by-step explanation:
Given
Radius of cone [tex]r=1.5\ in.[/tex]
Height of cone [tex]h=5\ in.[/tex]
Ice required to fill the cone=Volume of cone
The volume of a cone is
[tex]V=\dfrac{1}{3}\pi r^2h[/tex]
Put values
[tex]\Rightarrow V=\dfrac{1}{3}\times \dfrac{22}{7}\times 1.5^2\times 5=11.78\ in.^3[/tex]
