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On a given day, eight rabbits, 12 mice, and four snakes are present on the mountain range. If each animal is equally likely to be caught and consumed, what is the probability that the wolf will eat two rabbits?

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Answer:

7 / 69

Step-by-step explanation:

Rabbit = 8

Mice = 12

Snake = 4

Total = (8 + 12 + 4) = 24

If each animal has equal probability of being caught ;

Probability of catching a rabbit ;

Number of rabbits / total number of animals

P(catching 1 rabbit) = 8 / 24 = 1/3

P(catching 2nd rabbit) :

Number of rabbits left = 8 - 1 = 7

Total number of rabbits = 24 - 1 = 23

Hence, P(catching 2nd rabbit) = 7 /23

Probability of catching two rabbits :

1 /3 * 7/ 23 = 7 / 69

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