Answer:
New pressure = 7.51 atm
Explanation:
Given that,
Initial pressure, P₁ = 4.5 atm
Initial temperature, T₁ = 100°C = 100+273 = 373 K
Final temperature, T₂ = 350°C = 350 + 273 = 623 K
We need to find the new pressure. Using the below relation as follows :
[tex]\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\\\P_2=\dfrac{P_1T_2}{T_1}\\\\P_2=\dfrac{4.5\times 623}{373}\\\\P_2=7.51\ atm[/tex]
So, the new pressure is 7.51 atm.
