Explanation:
Charges,[tex]q_1=8\ \mu C=8\times 10^{-6}\ C[/tex]
[tex]q_2=-5\ \mu C=-5\times 10^{-6}\ C[/tex]
The distance between charges, r = 10 cm = 0.1 m
We need to find the magnitude and direction of the electric force. It is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\\\F=36\ N[/tex]
So, the required force between charges is 36 N and it is towards positive charge i.e. +8 μC.
