The jumping ability of the African desert locust was determined by measuring the acceleration as the locust jumps straight up, foll0wing the curve in (Figure 1). What was the maximum net force on this 0.48 g locust?

Locusts are known for their ability to jump large distances to avoid predation. The jump also serves to launch the adult locust into the air in order to initiate flight. Various aspects of this important behavior have been studied extensively, from muscle physiology and biomechanics, to the energy storage systems involved in powering the jump, and more. Less well understood are the mechanisms participating in control of the jump trajectory. Here we utilise video monitoring and careful analysis

onyebuchinnaji onyebuchinnaji · Answer 2 · 2021-09-30T14:24:58+02:00

The maximum net force on this locust is 0.039 N.

From the given graph we can deduce the following parameters;

maximum acceleration of the desert locust = 90 m/s²

the corresponding time of this jump = 30 ms

the mass of the locust, m = 0.48 g = 0.00048 kg

The maximum net force on this locust is calculated from Newton's second law of motion;

∑F = ma - mg

where;

g is acceleration due to gravity = 9.8 m/s² (since the motion is against gravity, it will have negative sign)

∑F = m(a - g)

∑F = 0.00048 (90 - 9.8)

∑F = 0.039 N

Thus, the maximum net force on this locust is 0.039 N.

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