Two angles of an isosceles triangle are X and (X+10) .find two possible values of X.

When two angles of an isosceles triangle are given in the form of x, then the value of a single angle can have two possible outcomes those are:

X can be [tex]56.66^\circ[/tex]
X can be [tex]53.33^\circ[/tex]

Given,

Two angles: X and [tex]\rm{X}+10[/tex]

As we know in an Isosceles triangle, the sum of all the angles is equal to[tex]180^\circ[/tex] and any of the two angles can be equal.

There can be two possible outcomes:

Case 1. When the two equal angles are X

[tex]\begin{aligned}\text{X}+\text{X}+(\text{X+10})&=180\\3\text{X}+10&=180\\3\text{X}&=180-10\\\text{X}&=\dfrac{170}{3}\\\text{X}&=56.66^\circ\end{aligned}[/tex]

Case 2: When the two equal angles are [tex]\rm{X}+10[/tex]

[tex]\begin{aligned}\text{X}+(\text{X}+10)+(\text{X}+10)&=180\\3\text{X}+20&=180\\3\text{X}&=180-20\\\text{X}&=\dfrac{160}{3}\\\text{X}&=53.33^\circ\end{aligned}[/tex]

Therefore, the two possible values of X can be [tex]56.66^\circ[/tex] and [tex]53.33^\circ[/tex]

To know more about the angles of the isosceles triangle, refer to the link:

https://brainly.com/question/12105959