contestada

A force of 31 N south is used to accelerate an object uniformly from rest to 8 m/s in 22 s. What is the mass of the object?

Respuesta :

nekosuzy

this question is centered around newtons second law f=ma

First you need to find the acceleration

[tex] acceleration = \frac{8 - 0}{22} [/tex]

that gives you 0.36 recurring(on both numbers) m/s²

mass= force ÷ acceleration

[tex] mass = \frac{31}{0.36recurring} [/tex]

mass= 85.25 kg

if you want to check

f=ma

85.25 × 0.36 recurring (remember its on both numbers not just 6) = 31 N

jcherry99

Answer:

Explanation:

Givens

F = 31 N

vi = 0

vf = 8 m/s

t = 22 seconds

m = ?

Formula

F = m ( vf - vi)/t

Solution

31 = m (8 - 0) / 22             Multiply both sides by 22

31 * 22 = 8 * m

8m = 682                          Divide by 8

m = 682 / 8

m = 85.25