Answer:
20°
Step-by-step explanation:
In circle with center O, PS is diameter.
[tex] m\angle PRS =90\degree [/tex]
(angle inscribed in semicircle)
PQRS is a cyclic quadrilateral.
Opposite angles of a cyclic quadrilateral are supplementary.
[tex] \therefore m\angle QPS + m\angle QRS = 180\degree [/tex]
[tex] \therefore (x\degree +25\degree) +(45\degree +90\degree) = 180\degree [/tex]
[tex] \therefore x\degree +25\degree + 45\degree +90\degree = 180\degree [/tex]
[tex] \therefore x\degree +160\degree = 180\degree [/tex]
[tex] \therefore x\degree = 180\degree-160\degree [/tex]
[tex]\huge\red {\therefore x\degree = 20\degree} [/tex]
