Geometry problem above^^^ In the figure at the right FGH ~ KLJ....

Answer:
x = 12
y = 4.5
Step-by-step explanation:
Since ∆FGH ~ ∆KLJ, therefore, we would have the following proportion:
[tex] \frac{FG}{KL} = \frac{GH}{LJ} = \frac{FH}{KJ} [/tex]
[tex] \frac{9}{y} = \frac{x}{6} = \frac{6}{3} [/tex]
✔️Let's solve for x using:
[tex] \frac{x}{6} = \frac{6}{3} [/tex]
Multiply both sides by 6
[tex] \frac{x}{6}*6 = \frac{6}{3}*6 [/tex]
[tex] x = \frac{6*6}{3} [/tex]
[tex] x = 12 [/tex]
✔️Solve for y using:
[tex] \frac{9}{y} = \frac{6}{3} [/tex]
Cross multiply
[tex] y*6 = 3*9 [/tex]
6y = 27
y = 27/6
y = 4.5