The length of this rectangle is 2sqrt19, the width of the rectangle is sqrt19. The value of its perimeter is?

Answer:
P = 6[tex]\sqrt{19}[/tex] units
A = 38 sq units
Step-by-step explanation:
P = 2[tex]\sqrt{19}[/tex] + 2[tex]\sqrt{19}[/tex] + 1[tex]\sqrt{19}[/tex] + 1[tex]\sqrt{19}[/tex]
P = 6[tex]\sqrt{19}[/tex]
A = 2[tex]\sqrt{19}[/tex] · [tex]\sqrt{19}[/tex]
A = 2 (19)
A = 38 sq units