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0.250 moles of gas are in a piston.The gas does 109 J of work while 240 J of heat are added. What is the change in internal energy?

(Be careful with + and - signs. +W = expansion, +Q =added, +ΔU = temp goes up)


Thank you!

Respuesta :

ayfat23

Answer:

+131Joules

Explanation:

Energy can be expressed using below expresion.

ΔE = (q + w).........eqn(1)

q will be + be if heat is gained hence, q= 240 J

work "w" will be - ve if work is done by the system, hence w= -109 J

Then substitute into eqn(1)

Change in Internal energy=

= (240 -109 )

= +131J

Eduard22sly

The change in the internal energy of the system which does 109 J of work while 240 J of heat are added is +131 J

Data obtained from the question

  • Mole of gas = 0.250 mole
  • Work (W) = –109 J (since work is done)
  • Heat (Q) = 240 J (since heat is added)
  • Change in internal energy (ΔU) =?

How to determine the change in the internal energy

The change in the internal energy of the system can be obtained as illustrated below:

ΔU = Q + W

ΔU = 240 + (–109)

ΔU = 240 – 109)

ΔU = +131 J

Thus, the change in the internal energy of the system is +131 J

Learn more about heat transfer:

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