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On a car trip you drive for 2 hours and 41 minutes on a highway at a speed of 107.0 km/h. Then you stop at a gas station to fill up your tank. You also eat a quick lunch. The whole break lasts 23 minutes. After the break you start your engine up and you switch to a state road. You drive for another 3 hours and 31 minutes at a speed of 67.0 km/h before you arrive to your destination. What was your average speed for the whole trip with the lunchbreak included

Respuesta :

Answer:

v = 79.3 km/h

Explanation:

  • By definition, the average speed, is the quotient between the total distance traveled and the time needed to travel that distance.
  • The total time, is the sum of three times: one while driving before stopping at the gas station (t₁), the time spent there (t₂) and the time since leaving the gas station until reaching the final destination (t₃) .
  • Let's convert these times to seconds first:

      [tex]t_{1} = 161 min* \frac{60s}{1min} = 9660 s (1)[/tex]

      [tex]t_{2} = 23 min* \frac{60s}{1min} = 1380 s (2)[/tex]

      [tex]t_{3} = 211 min* \frac{60s}{1min} = 12660 s (3)[/tex]

      [tex]t_{tot} =t_{1} +t_{2} +t_{3} = 9660s + 1380s + 12660s = 23700s (4)[/tex]

  • In order to find the total distance traveled, we need to add the distance traveled before stopping at the gas station (x₁) and the distance traveled after leaving it (x₂).
  • Applying the definition of average speed, we can find these distances as follows:

       [tex]x_{1} = v_{1} * t_{1} (5)[/tex]

       [tex]x_{2} = v_{2} * t_{3} (6)[/tex]

  • where v₁ = 107.0 km/h, and v₂= 67.0 km/h
  • As we did with time, let's convert v₁ and v₂ to m/s:

       [tex]v_{1} = 107.0 km/h*\frac{1000m}{1km}*\frac{1h}{3600s} = 29.7 m/s (7)[/tex]

      [tex]v_{2} = 67.0 km/h*\frac{1000m}{1km}*\frac{1h}{3600s} = 18.6 m/s (8)[/tex]

  • Replacing (7) and (1) in (5) we get x₁, as follows (in meters):

       [tex]x_{1} = v_{1} * t_{1} = 29.7 m/s * 9660 s = 286902 m (9)[/tex]

  • Doing the same for x₂ with (3) and (8):

       [tex]x_{2} = v_{2} * t_{3} = 18.6 m/s * 12660 s = 235476 m (10)[/tex]

  • Total distance traveled is just the sum of (9) and (10):

       [tex]x_{tot} = x_{1} +x_{2} = 286902 m + 235476 m = 522378 m (11)[/tex]

  • As we have already said, the average speed is just the quotient between (11) and (4), as follows:

       [tex]v_{avg} =\frac{\Delta x}{\Delta t} = \frac{522378m}{23700s} = 22.0 m/s (12)[/tex]

  • Converted back to km/h:

       [tex]v_{avg} = 22.0 m/s*\frac{1km}{1000m}*\frac{3600s}{1h} = 79.3 km/h (13)[/tex]