Answer:
log(x^3*y^(-2))
Step-by-step explanation:
two log rules you need to know for this question:
alogb = log(a^b)
logx + logy = logxy
you can start by getting rid of the term in front of the log, or a
also is it 2 minus or 2 times negative? im assuming it's 2 times negative because it is more likely
log (x^3) + log (y^-2) = log (x^3*y^-2)
