3. CONSTRUCTION A rectangular deck is built


around a square pool. The pool has side length s. The


length of the deck is 5 units longer than twice the side


length of the pool. The width of the deck is 3 units


longer than the side length of the pool. What is the


area of the deck in terms of s?





Did I do this right or was I supposed to leave it as a trinomial?

Respuesta :

Answer:

[tex]s^2+11s+15[/tex]

Step-by-step explanation:

Let side length of pool=s

According to question

Length of rectangular deck , l=2s+5

Width of rectangular deck, b=3+s

We have to find the area of deck in terms of s.

We know that

Area of square=[tex](side)^2[/tex]

Area of rectangle=[tex]l\times b[/tex]

Using the formula

Area of pool=[tex]s^2[/tex]

Area of (rectangular deck+ pool)=[tex](2s+5)(3+s)[/tex]

Now,

Area of rectangular deck

=[tex](2s+5)(3+s)-s^2[/tex]

[tex]=6s+2s^2+15+5s-s^2[/tex]

=[tex]s^2+11s+15[/tex]