Answer:
Annual deposit= $2,803.09
Explanation:
First, we need to calculate the monetary value at retirement:
FV= {A*[(1+i)^n-1]}/i
A= annual payment
FV= {22,000*[(1.08^25) - 1]} / 0.08
FV= $1,608,330.68
Now, the annual deposit required to reach $1,608,330.68:
FV= {A*[(1+i)^n-1]}/i
A= annual deposit
Isolating A:
A= (FV*i)/{[(1+i)^n]-1}
A= (1,608,330.68*0.08) / [(1.08^50) - 1]
A= $2,803.09