Find the equation of a line perpendicular to 4x−y=2 that contains the point (4,−2). Write the equation in slope-intercept form.

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Step-by-step explanation:

4x -y =2

-y = -4x + 2

y = 4x -2

slope = 4

perpendicular slope is negative inverse

so -1/4

y- -2 = -1/4(x - 4)

y+2 = -1/4x +1

y = -1/4x -1

As per slope-intercept form, the equation of a line perpendicular to

4x - y = 2 that contains the point (4,−2) is x + 4y + 4 = 0.

What is the slope-intercept form of a straight line?

The slope-intercept form of a straight line is y = mx + c.

Here, 'm' is the slope and 'c' ix the y-intercept of the given line.

The given equation is 4x - y = 2

Therefore, in slope-intercept form, this equation will be:

y = 4x - 2

Therefore, the slope of this line is m = 4.

The required line is perpendicular to the given line.

Therefore, the slope of the required line is

= - 1/m

= - 1/4

Again, the required line passes through the point (4, - 2).

Therefore, - 2 = - (1/4)4 + c

⇒ c = - 2 + 1

⇒ c = - 1

The equation of the required line is

y = - (1/4)x - 1

⇒ 4y = - x - 4

⇒ x + 4y + 4 = 0

Learn more  about the slope-intercept form of a straight line here: brainly.com/question/14534555

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