Answer:
x = -6 and x = 1
Step-by-step explanation:
Given the equation (x + 2) (x + 3) = 12
Equate to zero;
(x + 2) (x + 3) - 12 = 0
Expand
x^2+3x+2x+6-12 = 0
x^2+5x - 6 = 0
Factorize
x^2 + 6x - x - 6 = 0
x(x+6)-1(x+6) = 0
(x+6)(x-1) = 0
x+6 = 0 and x -1 = 0
x = -6 and x = 1
Hence the zeros are x = -6 and x = 1
