Answer: 0.175 moles of chlorine are need to produce 19.0 grams of [tex]FeCl_3[/tex]
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} FeCl_3=\frac{19.0g}{162.2g/mol}=0.117moles[/tex]
The balanced chemical equation is:
[tex]2Fe+3Cl_2\rightarrow 2FeCl_3[/tex]
According to stoichiometry :
2 moles of [tex]FeCl_3[/tex] require = 3 moles of [tex]Cl_2[/tex]
Thus 0.117 moles of [tex]FeCl_3[/tex] will require=[tex]\frac{3}{2}\times 0.117=0.175moles[/tex] of [tex]Cl_2[/tex]
Thus 0.175 moles of chlorine are need to produce 19.0 grams of [tex]FeCl_3[/tex]
